Question

class Base
{
public:
    virtual void foo() const
    {
        std::cout << "Base";
    }
};

class Derived : public Base
{
public:
    virtual void foo() const
    {
        std::cout << "Derived";
    }
};

Derived d; // call Base::foo on this object

Tried casting and function pointers but I couldn’t do it. Is it possible to defeat virtual mechanism (only wondering if it’s possible)?

Answer 1

To explicitly call the function foo() defined in Base, use:

d.Base::foo();