Question

class Class1
{
public:
    void print()
    {
        cout << "test" << endl;
    }

    void printl()
    {
        print();
    }
};

class Class2 : public Class1
{
public:
    void print()
    {
        cout << "test2" << endl;
    }
};

Why does print() not get overridden in Class2, is there any way a function can be overridden like this? (Without virtual functions). Thanks

    Class2 t;
    t.printl();

Answer 1

No. This is the entire reason for virtual functions.

Without a virtual method here, when printl() calls print(), it’s calling Class1.print(), which prints “test”. If you flag the method as virtual, then it will handle it as you were expecting.