Question

class DaemonThread extends Thread {

public void run() {
    System.out.println("Entering run method");

    try {
        System.out.println("In run Method: currentThread() is"
            + Thread.currentThread());

        while (true) {
            try {
                Thread.sleep(500);
            } catch (InterruptedException x) {
                System.out.println("hi");
            }

            // System.out.println("In run method: woke up again");

            finally {
                System.out.println("Leaving run1 Method");
            }
        }
    } finally {
        System.out.println("Leaving run Method");
    }

}

public static void main(String[] args) {
    System.out.println("Entering main Method");

    DaemonThread t = new DaemonThread();
    t.setDaemon(true);
    t.start();

    try {
        Thread.sleep(900);
    } catch (InterruptedException x) {}

    System.out.println("Leaving main method");
}

}

why second finally method not run…as i know finally method must have have to run whatever the condition is ..but in this case only first finally method, why not second finally run.

Answer 1

The println statement is never reached because of the while(true) loop that never ends!

If you ever leaves that loop, then the second finally block would be executed.