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Home/ Questions/Q 7021603
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T23:28:20+00:00 2026-05-27T23:28:20+00:00

class Employee { private String name; void setName(String n) { name = n; }

  • 0
class Employee {
    private String name;
    void setName(String n) { name = n; }
    String getName() { return name; }
}
interface Mungeable {
    void doMunging();
}
public class MyApp implements Mungeable {
    public void doMunging() { ; }
    public static void main(String[] args) {
        Employee e = new Employee();
        e.setName("bob");
        System.out.print(e.getName());
    } 
}

And the possible answers:

Which are true? (Choose all that apply.)
A. MyApp is-a Employee.
B. MyApp is-a Mungeable.
C. MyApp has-a Employee.
D. MyApp has-a Mungeable.
E. The code is loosely coupled.
F. The Employee class is well encapsulated.

While answering the above question i selected options B,C,E and F

Apparently the only correct answers are B,E and F. For MyApp to have a Has-A relationship with Employee both have to be in the same inheritance tree hierarchy. Is this correct? I thought that if a class has the object as a member it automatically has a Has-A relationship.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T23:28:21+00:00Added an answer on May 27, 2026 at 11:28 pm

    For MyApp to have a Has-A relationship with Employee both have to be
    in the same inheritance tree hierarchy. Is this correct?

    It is not correct.

    I thought that if a class has the object as a member it automatically
    has a Has-A relationship.

    You were right. Point is, MyApp does not have Employee as a member.

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