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Home/ Questions/Q 7405149
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:21:33+00:00 2026-05-29T05:21:33+00:00

class example() { function shout($var) { echo ‘shout’.$var; } function whisper($var, $bool) { if($bool)

  • 0
class example()
{
    function shout($var)
    {
        echo 'shout'.$var;
    }

    function whisper($var, $bool)
    {
        if($bool)
        {
           echo $var;
        }
    }
}

$obj = new example();

if($var) 
{
    $func = $obj->shout();
}else
{
    $func = $obj->whisper();
}

I want to prepare the function variable first for later use instead of putting conditions in a loop. Is there a possible way to do it?

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:21:33+00:00Added an answer on May 29, 2026 at 5:21 am

    You can put the function name in a string:

    if($var) 
    {
        $func = 'shout';
    }else
    {
        $func = 'whisper';
    }
    

    Later on:

    $obj->$func
    

    You can also use a callback:

    if($var)
    {
        $func = array($obj, 'shout');
    }else
    {
        $func = array($obj, 'whisper');
    }
    

    Later:

    call_user_func($func);
    

    or:

    call_user_func_array($func, $args);
    
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