Question

class MyClass {
    public: MyClass(int a) : a(a) { }
    int a;
};

#include <iostream>
void print(MyClass* a) { std::cout << a->a << std::endl; }

int main() {
    print(&static_cast<MyClass&&>(MyClass(1337)));
    return 0;
}

This doesn’t work with GCC 4.6, while it used to work in a previous version.

Now it says: taking address of xvalue (rvalue reference).

Is there any way to securely pass the address of an rvalue to another function?

Answer 1

is: there is anyway to securely pass an rvalue reference (a.k.a. address of temporary) to another function without boringly storing it in a variable just to do that?

Yes, there is, like in the next example :

#include <iostream>

class MyClass {
       public: MyClass(int a) : a(a) { }
       int a;
   };


void print(MyClass&& a) { std::cout << a.a << std::endl; }

int main() {
    print( MyClass(1337) );
}