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Home/ Questions/Q 1097841
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T00:29:24+00:00 2026-05-17T00:29:24+00:00

$class = new Class; $foo = json_decode($_POST[‘array’]); In this highly contrived example, I have

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$class = new Class;
$foo = json_decode($_POST['array']);

In this highly contrived example, I have a class with its own functions and variables, blah blah.

I also just decoded a JSON string, so those values are now in$foo. How do I move the elements in $foo over to $class, so that:

$foo->name becomes $class->name?

Would be trivial if I knew what all the elements were, yes… except for the sake of being dynamic, let’s say I want them all transferred over, and I don’t know their names.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T00:29:24+00:00Added an answer on May 17, 2026 at 12:29 am

    You could use get_object_vars:

    $vars = get_object_vars($foo);
    foreach ($vars as $key => $value) {
        $class->$key = $value;
    }
    

    You could also implement this in your class:

    public function bindArray(array $data) {
        foreach ($data as $key => $value) {
            $this->$key = $value;
        }
    }
    

    And then cast the object into an array:

    $obj->bindArray( (array) $foo );
    

    or add a method to do that too:

    public function bindObject($data) {
         $this->bindArray( (array) $data );
    }
    
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