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Home/ Questions/Q 9302661
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T23:18:26+00:00 2026-06-18T23:18:26+00:00

class SomeClass1 { void method1() { } public void method2() { } private void

  • 0
class SomeClass1 {
  void method1() { }
  public void method2() { }
  private void method3() { }
  protected void method4() { }
}
class DemoClass{
  public static void main(String[] parameters) {
    SomeClass1 sc = new SomeClass1();
    sc.method1();
    sc.method2();
    sc.method4();
  }
}

Protected methods can only be accessed by classes that inherits the super class. As we can see here DemoClass does not extend SomeClass. But yet, it is able to access the protected method. How is this possible?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T23:18:27+00:00Added an answer on June 18, 2026 at 11:18 pm

    That’s because they are in the same package:

    The protected modifier specifies that the member can only be accessed within its own package (as with package-private) and, in addition, by a subclass of its class in another package.

    (Link to the documentation).

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