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Home/ Questions/Q 8573767
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T19:19:32+00:00 2026-06-11T19:19:32+00:00

class SomeUI { SocketMessageSender messageSender; // ensure that its initialized … private void bSendMessageActionPerformed(java.awt.event.ActionEvent

  • 0
class SomeUI     
{ 
SocketMessageSender messageSender; 
// ensure that its initialized ... 
private void bSendMessageActionPerformed(java.awt.event.ActionEvent evt) {
        try {
            // TODO add your handling code here:
            messageSender.sendMessage(jMessage.getText()); 
            jMessage.setText("");
        } catch (IOException ex) {
            Logger.getLogger(TeKServer.class.getName()).log(Level.SEVERE, null, ex);
        }
    } 
}

ERROR: Exception in thread “AWT-EventQueue-0” java.lang.RuntimeException: Uncompilable source code – Erroneous sym type: bSendMessageActionPerformed

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T19:19:33+00:00Added an answer on June 11, 2026 at 7:19 pm

    Why do you keep opening the socket and closing it on every button click. Create a class that allow you to keep the socket open for as long as your application run. The socket connection can be done when the application starts.You can try out the following class

    public class SocketMessageSender
    {
        private String host;
        private int port;
        private DataOutputStream dos;
    
        public SocketMessageSender(String host, int port)
        {
            this.host = host;
            this.port = port;
        }
    
        // call when application starts
        public void initConnection() throws IOException
        {
            InetAddress address = InetAddress.getByName(host);
            Socket connection = new Socket(address, port);
            dos = new DataOutputStream(connection.getOutputStream());
        }
    
        //call from button click
        public void sendMessage(String message) throws IOException
        {
            if(dos != null)
            {
                dos.writeUTF(message);
                dos.flush();
            }
        }
    
        // call when application exits
        public void closeConnection() throws IOException
        {
            if(dos!= null)
            {
                dos.close();
            }
        }
    }
    

    Hope it helps …

    Assume you have a class like

    class SomeUI
    {
       SocketMessageSender messageSender;
       // ensure that its initialized ...
    
    
    
     private void bSendMessageActionPerformed(java.awt.event.ActionEvent evt) {
        messageSender.sendMessage(jMessage.getText());
        jMessage.setText("");
     }
    }
    

    I think that the class signature should be something like this ….

    public class MyPanel extends JPanel implements ActionListener
    {
        private SocketMessageSender messageSender;
        private Message jMessage = new Message();// This is just a temp class, replace this with your class
    
        public MyPanel()
        {
            messageSender = new SocketMessageSender("some host", 8080);
            try
            {
                messageSender.initConnection();
            }
            catch(IOException e)
            {
                 Logger.getLogger(MyPanel.class.getName()).log(Level.SEVERE, null, e);
            }
        }
    
        @Override
        public void actionPerformed(ActionEvent e)
        {
            try {
                // TODO add your handling code here:
                messageSender.sendMessage(jMessage.getText()); 
                jMessage.setText("");
            } catch (IOException ex) {
                Logger.getLogger(MyPanel.class.getName()).log(Level.SEVERE, null, ex);
            }
        }
    }
    
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