Question

class temp;

temp *t;

void foo() { temp foo2; t[1] = foo2; }

int main() { 
    t = new temp[100];
    foo();
    //t[1] is still in memory?
}

• If i want an array of classes like this, am i going to have to use
  pointer to pointer? (and use ‘new’
  on each element in the array) E.G:
  temp **t;
• if i want to make an
  array of 100 ptr to ptr i have todo
  temp **t = new temp[100][1]; is
  there a better way to do that without
  4 square brackets?

Answer 1

The code:

t = new temp[100];

constructs an array 100 objects of type temp. A safer way to do the same thing is:

std::vector <temp> t(100);

which absolves you of ever having to call delete[] on the array.