Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 112809
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 11, 20262026-05-11T02:36:11+00:00 2026-05-11T02:36:11+00:00

class test { public: test &operator=(const test & other){} // 1 const test &

  • 0
class test { public:     test &operator=(const test & other){} // 1     const test & operator+(const test& other) const {} // 2     const test & operator+(int m) {} //3 private:     int n; };  int main() { test t1 , t2, t3;  // this works fine  t1 = t2.operator+(t3) , calls  2 and 1 t1 = t2 + t3;   // this works fine    t1 = t2.operator+ (100). calls 3 and 1 t1 = t2 + 100;  //this works fine t1 = (t2.operator+ (100)).operator+ (t3) t1 = t2 + 100 +t3;  //why is the error in this one  ???? // it should be t1 = (t2.operator+ (t3)).operator+ (100) t1  =  t2 + t3 + 100;   return 0; } 
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. 2026-05-11T02:36:12+00:00Added an answer on May 11, 2026 at 2:36 am

    Because object returned by t2+t3 is const, and you cannot call its non-const function (3).

    It works fine in case of ‘t1 = t2 + 100 +t3;’, because object returned by t2+100 is const too, but you are calling its const function (2), which is ok.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 95k
  • Answers 95k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer Yes you can store it in the session safely. You… May 11, 2026 at 7:02 pm
  • Editorial Team
    Editorial Team added an answer I've never done it myself, but I know you can… May 11, 2026 at 7:02 pm
  • Editorial Team
    Editorial Team added an answer See this previous SO question, which covers bash. Tcsh provides… May 11, 2026 at 7:02 pm

Related Questions

I've been comparing a STL implementation of a popular XmlRpc library with an implementation
What's wrong with the following little program that passes a function object? #include <iostream>
Couldn't creatively shorten the title :) I have been using a variation of the
When writing a class to act as a wrapper around a heap-allocated object, I

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.