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Home/ Questions/Q 988877
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T05:42:03+00:00 2026-05-16T05:42:03+00:00

Client: string value = <?xml version=1.0?><person><firstname>john</firstname><lastname>smith</lastname> <person/>; using (HttpResponseMessage response = m_RestHttpClient.Post(new/customerxml/+value2, frm.CreateHttpContent())) {

  • 0

Client:

string value = "<?xml version=1.0?><person><firstname>john</firstname><lastname>smith</lastname> <person/>";

using (HttpResponseMessage response = m_RestHttpClient.Post("new/customerxml/"+value2, frm.CreateHttpContent()))
{

}

Server:

[OperationContract]
[WebInvoke(UriTemplate = "new/customerxml/string={value}", Method = "POST", BodyStyle = WebMessageBodyStyle.Wrapped, ResponseFormat = WebMessageFormat.Xml, RequestFormat = WebMessageFormat.Xml)]
public string NewCustomer(string value)
{
        return value;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T05:42:04+00:00Added an answer on May 16, 2026 at 5:42 am

    That’s because WCF sniffs the content and decides you are uploading XML, not a string. Assuming you are using the HttpClient from the WCF REST Starter kit, try this:

        string value = "<?xml version=1.0?><person><firstname>john</firstname><lastname>smith</lastname> <person/>";
    
    var content = HttpContentExtentions.CreateDataContract(value, typeof(string));
    using (HttpResponseMessage response = m_RestHttpClient.Post("new/customerxml/"+value2, content)
        {
          ...
        }
    
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