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Asked: May 10, 20262026-05-10T20:52:57+00:00 2026-05-10T20:52:57+00:00

Code below is not working as expected to detect if it is in design

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Code below is not working as expected to detect if it is in design mode (VS.Net 2003 – Control Library):

if (this.Site != null && this.Site.DesignMode == true)
{
// Design Mode
}
else
{
// Run-time
}

It is used in a complex user control, deriving from another user control and including other user controls on it.
Is there another way to detect design time in a VS.NET 2003 or what is the problem with the code above?

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  1. 2026-05-10T20:52:58+00:00Added an answer on May 10, 2026 at 8:52 pm

    DesignMode won’t work from inside a constructor. Some alternatives (not sure if they work in 1.1) are

    if (System.ComponentModel.LicenseManager.UsageMode == System.ComponentModel.LicenseUsageMode.Designtime)

    or

    call GetService(typeof(IDesignerHost)) and see if it returns something.

    I’ve had better luck with the first option.

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