Question

Code:

 catch (IOException e) {
        LOGGER.error("IOException exception happened");
        //now need throw again the same exception to be 
                       //catched in    the    upper method
    }

But when I try simply:

  catch (IOException e) {
        LOGGER.error("IOException exception happened");
        //now need throw again the same exception to be 
                       //catched in    the    upper method
               throw e;
    }

Eclipse supposes to me put “throw e” in try catch block. But this is nonsense.
How fix this problem?
Thanks.

Answer 1

Since IOException is a checked exception, that method needs to be declared as throwing IOException if you want it to propagate. For example:

void myMethod() throws IOException {
    try {
        //code
    }
    catch(IOException e) {
        LOGGER.error("IOException exception happened");
        throw e;
    }
}