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Home/ Questions/Q 7443117
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T11:16:54+00:00 2026-05-29T11:16:54+00:00

Code goes first: void foo(int x) { void bar(int); //is this forward-decl legal? bar(x);

  • 0

Code goes first:

void foo(int x)
{
    void bar(int);  //is this forward-decl legal?
    bar(x);
}

void bar(int x)
{
    //do stuff
}

In the code above, foo calls bar, usually I put the forward-decl of bar outside of foo, like this:

void bar(int);
void foo(int x) 
{
    bar();
}

First, I think it’s OK to put bar‘s forward-decl inside foo, right?

Second, consider this, if bar is a static function like this:

static void bar(int x)
{
    //do stuff
}

Then how should I forward-declare it? I mean should the forward-decl take or omit the static?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T11:16:54+00:00Added an answer on May 29, 2026 at 11:16 am
    1. Yes it’s legal to put a forward-declaration inside another function. Then it’s only usable in that function. And the namespace of the function you put it inside will be used, so make sure that matches.

    2. The Standard says: “The linkages implied by successive declarations for a given entity shall agree.” (section 7.1.2). So yes, the prototype must be static also. However, it doesn’t look like putting a prototype of a static linkage function inside another function is allowed at all. “There can be no static function declarations within a block” (same section).

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