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Home/ Questions/Q 8711793
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T04:58:18+00:00 2026-06-13T04:58:18+00:00

CODE: <input type=checkbox name=discountedItem <?php if (isset($_POST[‘discountedItem’])) echo checked . . value=’y’; ?> />

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CODE:

<input type="checkbox" name="discountedItem" <?php if (isset($_POST['discountedItem'])) echo "checked" . " " . "value='y'"; ?> />

How can I transform this into an if statement so that if it’s not checked the value is n?

I tried:

<input type="checkbox" name="discountedItem" <?php if (isset($_POST['discountedItem'])) { echo "checked" . " " . "value='y'"; } else { echo "value='n'"; } ?> />

Didn’t work. The value was just NULL.

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  1. Editorial Team
    Editorial Team
    2026-06-13T04:58:20+00:00Added an answer on June 13, 2026 at 4:58 am

    The value= is never submitted if the checkbox isn’t set.

    You can’t have your n with a checkbox. Consider a radio button. Or simply adapt your processing logic (the if you referred to) not to look for strings, but any present value.

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