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Home/ Questions/Q 3279454
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T19:35:40+00:00 2026-05-17T19:35:40+00:00

Code: $(‘#Inputfield’).keyup(function(e) { if(e.which == 13) { functionXyz(); } else { functionZyx(); } });

  • 0

Code:

$('#Inputfield').keyup(function(e)
        {
            if(e.which == 13)
            {
                functionXyz();
            }
            else
            {
                functionZyx();
            }
    });  


$(document).keyup(function(exit) {
              if (exit.keyCode == 27) { functionZzy(); }
});

Question: How to remove the keyup event handler of keyCode == 27 and keep the other $(document).keyup event handlers intact?

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  1. Editorial Team
    Editorial Team
    2026-05-17T19:35:41+00:00Added an answer on May 17, 2026 at 7:35 pm

    You have to use a named function so you can reference that specific handler when calling .unbind(), like this:

    function keyUpFunc(e) {
      if (e.keyCode == 27) { functionZzy(); }
    }
    $(document).keyup(keyUpFunc);
    

    Then later when unbinding:

    $(document).unbind("keyup", keyUpFunc);
    
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