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Editorial Team
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Asked: 2026-05-26T06:27:38+00:00

code is as below: <?php //set up variables $theData = ‘<?xml version=1.0?> <note> <to>php.net</to>

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code is as below:

<?php
//set up variables
$theData = '<?xml version="1.0"?>
<note>
    <to>php.net</to>
    <from>lymber</from>
    <heading>php http request</heading>
    <body>i love php!</body>
</note>';
$url = 'http://www.example.com/script.php';

//create the httprequest object                
$httpRequest_OBJ = new httpRequest($url, HTTP_METH_POST, $options);
//add the content type
$httpRequest_OBJ->setContentType = 'Content-Type: text/xml';
//add the raw post data
$httpRequest_OBJ->setRawPostData ($theData);
//send the http request
$result = $httpRequest_OBJ->send();
//print out the result
echo "<pre>"; print_r($result); echo "</pre>";
?>

Now httprequest calls the script here:

http://www.example.com/script.php

Over there I want to access the object, so that I can manipulate the data and send it back:

$httpRequest_OBJ->setRawPostData ($theData);

but it does not work. I tried $_POST['theData'], but this only works if you use $r->**addPostFields**(array('user' => 'mike', 'pass' => 's3c|r3t'));

How can I access the object $theData?

Thanks.

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1 Answer

  1. Editorial Team

    I think what you are after is php://input

    So you can get the whole lot of XML that you posted like this:

    $fp = fopen('php://input','r');
$data = '';
while (!feof($fp)) $data .= fread($fp,1024);
// $data should now contain the XML posted in your example

    As a side note, I think the line

    $httpRequest_OBJ->setContentType = 'Content-Type: text/xml';

    …should probably just read

    $httpRequest_OBJ->setContentType = 'text/xml';
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