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Home/ Questions/Q 9252287
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T10:54:27+00:00 2026-06-18T10:54:27+00:00

Code is here void A::fun() { QAction* act = new QAction(this); QAction* act2 =

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Code is here

void A::fun()
{
    QAction* act = new QAction(this);
    QAction* act2 = new QAction(this);
    connect(act, QAction::triggered, [this, &act2]() {...; act2.setDisable(true);}
                              // crash when &act2 is used to capture the variable
                              // but it is okay using act2 to capture the variable
}

What is the reason? Thanks.

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  1. Editorial Team
    Editorial Team
    2026-06-18T10:54:28+00:00Added an answer on June 18, 2026 at 10:54 am

    You are taking a reference of act2 even though it is a pointer that will go out scope, that is why copying the pointer works.

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