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Home/ Questions/Q 7919629
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T15:55:55+00:00 2026-06-03T15:55:55+00:00

code is simple def bubble_sort(l): for i in xrange(0, len(l)-1) : for n in

  • 0

code is simple

def bubble_sort(l):
    for i in xrange(0, len(l)-1) :
        for n in xrange(0, len(l)) :
            if l[i] > l[i+1] :
                l[i], l[i+1] = l[i+1], l[i]

lst = [[1, 8, 2], [3, 2, 5], [2, 13, 3], [2, 5, 5], [2, 5, 6], [5, 11, 6], [5, 5, 6]]
print(lst)
bubble_sort(lst)
print(lst)

result:

[[1, 8, 2], [3, 2, 5], [2, 13, 3], [2, 5, 5], [2, 5, 6], [5, 11, 6], [5, 5, 6]]
[[1, 8, 2], [2, 13, 3], [2, 5, 5], [2, 5, 6], [3, 2, 5], [5, 5, 6], [5, 11, 6]]

the sort is not correct.

why?

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  1. Editorial Team
    Editorial Team
    2026-06-03T15:55:56+00:00Added an answer on June 3, 2026 at 3:55 pm

    The problem is that you’re making only one iteration, while in bubble sort you should iterate over and over again until there are no swapped pairs anymore. Like this:

    def bubble_sort(l):
        ok = False
    
        while not ok:
            ok = True
            for i in range(len(l) - 1):
                if l[i] > l[i+1]:
                    l[i], l[i+1] = l[i+1], l[i]
                    ok = False
    
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