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Home/ Questions/Q 9267001
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T14:26:53+00:00 2026-06-18T14:26:53+00:00

Code like this: fileArray = [‘a.json’,’b.json’,’c.json’] dict = {} fileArray.map (f) -> fs.readFile f,

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Code like this:

fileArray = ['a.json','b.json','c.json']
dict = {}
fileArray.map (f) ->
  fs.readFile f, (err, data) ->
    json.parse data, (k, v) ->
      dict[k] = v

I want to write the dict object to a file. How can I wait for all asynchronous functions finish?

Or is there any way else to do this?

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  1. Editorial Team
    Editorial Team
    2026-06-18T14:26:55+00:00Added an answer on June 18, 2026 at 2:26 pm

    You can do it manually like this

    fileArray = ['a.json','b.json','c.json']
    dict = {}
    counter = 0
    fileArray.map (f) ->
        fs.readFile f, (err, data) ->
            counter +=1
            json.parse data, (k, v) ->
                dict[k] = v
            if counter >= fileArray.length
                fs.writeFile("mydict.txt", dict.toString())
    

    or you use a async library (for example https://github.com/caolan/async)

    fileArray = ['a.json','b.json','c.json']
    dict = {}
    counter = 0
    read = (file)->
        fs.readFile f, (err, data) ->
            json.parse data, (k, v) ->
                dict[k] = v
    
    fns = ((do (file) -> read(file)) for file in fileArray)
    #use the async lib
    async.parallel fns, -> fs.writeFile "mydict.txt", json.stringify(dict)
    

    Please take care I havent tested this.

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