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Home/ Questions/Q 7025231
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T23:56:48+00:00 2026-05-27T23:56:48+00:00

Code printf(Doing functionname… ); if (functionname(args) == -1) { perror(functionname); } else { printf(ok\n);

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Code

printf("Doing functionname... ");
if (functionname(args) == -1)
{
    perror("functionname");
}
else
{
    printf("ok\n");
}

Expected behavior

Doing functionname… ok

OR

Doing functionname… functionname: Error blah blah

Actual behavior

However stderr and stdout are different output streams so the result looks like this,

functionname: Error blah blah

Doing functionname…

What are the possible workarounds?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T23:56:49+00:00Added an answer on May 27, 2026 at 11:56 pm

    Flush the output stream. stdout, by default, is line buffered; so the output is only effectivelly written when it sees a ‘\n’ (or when the buffer gets filled). By contrast, stderr is not buffered by default, so every single character is output immediately.

    printf("blah blah blah");
    fflush(stdout);
    

    If you terminate the string with a ‘\n’, the stream will be flushed with no need for a specific fflush statement.

    printf("blah blah blah\n"); /* stream flushed */
    

    Alternatively, print your information stuff to the stderr stream

    fprintf(stderr, "Doing functioname...");
    

    This has the advantage that users may redirect all information messages to /dev/null

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