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Home/ Questions/Q 7435825
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T10:08:24+00:00 2026-05-29T10:08:24+00:00

Code says it all: teststring = helloworld$ string_from_user = world$ regexp = Regexp.escape(string_from_user) #

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Code says it all:

teststring = "helloworld$"
string_from_user = "world$"
regexp = Regexp.escape(string_from_user) # assigns "world\\$"
p teststring =~ Regexp.new(regexp) # prints 0 => match found
p teststring =~ /regexp/ # prints nil => no match

That the first one matches is mentioned in the Regexp.escape docs.
But why doesn’t the second version match?

I’m concerned because I need to pass this regexp to third party Ruby code. The string comes from the user, so I want to escape it. Then, in some situations, I might add additional regexp symbols to this user’s string. For example, I might pass "^helloworld\\$" so that third party code would match strings like "helloworld$othercontent".

I am worried that if the third party code uses =~ /regexp/ instead of =~ Regexp.new(regexp), I will be in trouble, because there will be no match as indicated by the code above.

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  1. Editorial Team
    Editorial Team
    2026-05-29T10:08:25+00:00Added an answer on May 29, 2026 at 10:08 am

    Because /regexp/ is a regexp matching the string "regexp". Perhaps you meant /#{regexp}/?

    Edit: I take it, from reading your question more fully, that you’re passing a string into third party code that you know will be making a Regexp from that string. In which case, you should be safe. As noted above, /regexp/ cannot possibly be what they’re doing, because it’s just wrong. They must be using Regexp.new() or something similar.

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