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Home/ Questions/Q 6828151
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T22:20:58+00:00 2026-05-26T22:20:58+00:00

Code would explain this much better :) def a(): x=0 def b(z=x): print(X: %d,

  • 0

Code would explain this much better 🙂

def a():
    x=0
    def b(z=x):
        print("X: %d, Z: %d" % (x,z,))
    x=5
    b()

Result:

X: 5, Z: 0

What’s going on here?

(Ok, now I’ve figured it out)

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T22:20:58+00:00Added an answer on May 26, 2026 at 10:20 pm

    Ok, the answer from the Python docs is:

    Default parameter values are evaluated when the function definition is executed. This means that the expression is evaluated once, when the function is defined, and that the same “pre-computed” value is used for each call.

    Fair enough.

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