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Home/ Questions/Q 8715019
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T05:44:45+00:00 2026-06-13T05:44:45+00:00

Coding in UNIX make , I have written: cat $ sString | grep sSubstring

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Coding in UNIX make, I have written:

cat $ sString | grep sSubstring > sResult

So I want to check if sString contains sSubString and, if it does, put the result in sResult.

Background: I have put the contents of a file in sString – if sSubString is present in the file, then sResult contains each line of the file containing sSubString.

This works fine when sSubString is in sString. When it is not, I get Error Code 1.

How can I handle this correctly? The complete code is:

cat $ sString | grep sSubstring > sResult
if [ -s sResult -gt 0 ];then \
(echo "substring present" ) \
else (echo "substring not present" ) ;fi

(With the error code, I never get to the else .)

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  1. Editorial Team
    Editorial Team
    2026-06-13T05:44:46+00:00Added an answer on June 13, 2026 at 5:44 am

    Sounds like you might need this

    cat $ sString | { grep sSubstring || true; } > sResult
    

    See this solution. The problem is that when grep doesn’t find anything it returns a non-zero exit code. make will then think it is an error. So you just need to make sure that the command always returns a zero exit code by or-ing the exit code of grep with the exit code of true. The exit code of true is always 0.

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