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Home/ Questions/Q 722919
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:02:47+00:00 2026-05-14T06:02:47+00:00

$.Comment = function() { this.alertme = Alert!; } $.Comment.prototype.send = function() { var self

  • 0

$.Comment = function() {
this.alertme = “Alert!”;
}

$.Comment.prototype.send = function() {

  var self = this;
  $.post(
    self.url,
    {
      'somedata' : self.somedata
    },
    function(data, self) {
      self.callback(data);
    } 
  );

}

$.Comment.prototype.callback = function(data) {
  alert(this.alertme);
}

When I’m calling $.Comment.send() debugger is saying to me that self.callback(data) is not a function

What am I doing wrong?

Thank you

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:02:47+00:00Added an answer on May 14, 2026 at 6:02 am

    You don’t want to declare self as an argument to the success function. If you remove that declaration, you’ll pick up the local variable, which is what you want. E.g.:

    $.Comment = function() {
        this.alertme = "Alert!";
    }
    
    $.Comment.prototype.send = function() {
    
        var self = this;
        $.post(
            self.url,
            {
                'somedata' : self.somedata
            },
            function(data) {         // <== removed `self` argument
                self.callback(data); // <== now sees `self` local var
            }
        );
    
    }
    
    $.Comment.prototype.callback = function(data) {
        alert(this.alertme);
    }
    
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