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Home/ Questions/Q 6630277
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Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T22:22:49+00:00 2026-05-25T22:22:49+00:00

community! Would be great if u could help me w/ my issue. I got

  • 0

community! Would be great if u could help me w/ my issue.

I got a custom class loader which is gonna to be java.system.class.loader – it holds
urls where to find classes. Like this:

public class TestSystemClassLoader extends URLClassLoader {

    public TestSystemClassLoader(ClassLoader parent) {
    super(classpath(), parent);
    }

    private static URL[] classpath() {
    try {
        // I got junit-4.8.2.jar under this url.
        URL url = new File("D:\\Work\\lib\\junit-4\\").toURI().toURL();
        return new URL[] { url };
    }
    catch (MalformedURLException e) {
        throw new IllegalArgumentException(e);
    }
    }
}

Then I run the java(JDK6) with -Djava.system.class.loader=TestSystemClassLoader eg.TestMain,
where eg.TestMain’ main:

public static void main(String[] args) throws Exception {
    // here I got system CL which is what I want.
ClassLoader cl = Thread.currentThread().getContextClassLoader();
    // here I got: "Exception in thread "main" java.lang.ClassNotFoundException: org.junit.runners.JUnit4"
Class<?> clazz = Class.forName("org.junit.runners.JUnit4", true, cl);
}

The thing which makes me mad is that if I unpack/unzip/unjar the junit-4.8.2.jar – then
eg.TestMain would work!

The question is – how to tell java(JDK6) that I want whole directory to be in classpath,
i.e. any file residing in the directory.

Thanks in advance!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T22:22:50+00:00Added an answer on May 25, 2026 at 10:22 pm

    Find all the jars and add them:

    private static URL[] classpath() {
        try {
            File file = new File("D:\\Work\\lib\\junit-4\\");
            List<URL> urls = new ArrayList<URL>();
            for (File f : file.listFiles()) {
                if (f.isFile() && f.getName().endsWith(".jar")) {
                    urls.add(f.toURI().toURL());
                }
            }
    
            return urls.toArray(new URL[0]);
        }
        catch (MalformedURLException e) {
            throw new IllegalArgumentException(e);
        }
    }
    
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