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Home/ Questions/Q 8441069
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T08:28:09+00:00 2026-06-10T08:28:09+00:00

Compiling the following with MinGW 4.6.2 (with g++ -g -std=c++0x), gdb doesn’t seem to

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Compiling the following with MinGW 4.6.2 (with g++ -g -std=c++0x), gdb doesn’t seem to want catch the std::out_of_range if I try catch throw. if I throw it manually it catches fine, am I doing something wrong?

#include <stdexcept>
#include <vector>

int main()
{
    std::vector<char> vec(10);
    try {       
        vec.at(10); // this won't be caught by gdb

        // throw std::out_of_range(""); // this will
    }
    catch (std::out_of_range const& e) {        
    }   
}
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  1. Editorial Team
    Editorial Team
    2026-06-10T08:28:10+00:00Added an answer on June 10, 2026 at 8:28 am

    As you’ve seeen, the exception from std::vector::at() is thrown by __throw_out_of_range which is a function inside libstdc++.so, so I suspect there’s some problem on Mingw that prevents GDB from setting a catchpoint in a shared library. Or maybe your libstdc++ wasn’t built with -g.

    If your GCC was configured with --enable-libstdcxx-debug you would have a second set of libs built with -O0 -g that might work better when debugging, but that option isn’t used often.

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