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Home/ Questions/Q 6883327
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T05:22:08+00:00 2026-05-27T05:22:08+00:00

Consider a string: str1=abcd<aaa>some thing <#^&*some more!#$@ </aaa> abcdefgasf <aaa>asfaf %^&*$saf asf %$^ </aaa>

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Consider a string:

str1="abcd<aaa>some thing <#^&*some more!#$@ </aaa> 
                            abcdefgasf <aaa>asfaf %^&*$saf  asf %$^ </aaa>
                            <another tag> some text </another tag>
                            <aaa>sfafaff#%%%^^</aaa> "

Now in the above string how to replace the special characters and white spaces that are present between the tag <aaa> and </aaa>?

The replacing character should be ‘_’.

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  1. Editorial Team
    Editorial Team
    2026-05-27T05:22:09+00:00Added an answer on May 27, 2026 at 5:22 am

    Here is a possible solution, is a little bit complex, so I’ll explain it step by step.

    We are going to use a module called re, for regular expressions:

    import re
    

    OK, here is our string:

    s = 'abcd<aaa>some thing <#^&*some more!#$@ </aaa> abcdefgasf <aaa>asfaf %^&*$saf  asf %$^ </aaa> <another tag> some text </another tag> <aaa>sfafaff#%%%^^</aaa>'
    

    First, let’s get all the content inside the tags:

    inside_tags = re.findall('<aaa>(.+?)</aaa>', s)
    

    Now, lets iterate through each content of inside_tags and replace the special characters:

    cleaned_contents = [ re.sub('[^\w ]', '_' , content) for content in inside_tags ]
    

    So, in cleaned_contents now we have the contents inside the tags, but with the special characters replaced. Now, lets zip (join in a tuple) each content inside a tag with its “cleaned” content:

    zipped = zip(inside_tags, cleaned_contents)
    

    And finally, search the tag contents in the string and replace them with the new cleaned content:

    for old, new in zipped:
        s = s.replace(old, new)
    

    NOTE: If you don’t understand something (there is a bunch of weird stuff here, like ?, [^\w ], zip) post your comment below and I’ll explain it.

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