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Home/ Questions/Q 8677193
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T20:23:37+00:00 2026-06-12T20:23:37+00:00

Consider below code: public class Test{ public static void main(String str[]){ B b =

  • 0

Consider below code:

public class Test{
  public static void main(String str[]){
     B b = new B();
     A a1 = (A)b;//Explicit type conversion
     A a2 = b;
  }
}
class A{}
class B extends A{}

In the above code are the two line:

A a1 = (A)b;//Explicit type conversion
A a2 = b;

Equivalent? If not then what is the difference between the two and if yes then is there any scenario in java where we need to explicitly convert a sub class object into a super class object?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T20:23:39+00:00Added an answer on June 12, 2026 at 8:23 pm

    The explicit type casting of the reference, not the object) is redundant and some IDEs will suggest you drop it.

    If you do

    A a1 = (A)b;
    

    You can still do

    B b2 = (B) A;
    

    to cast the reference back to type of B.

    Note: the object is not altered in any way and is always a B

    there is no scenario in java where you would need it?

    The only time you need an upcast is in method selection.

    void method(Object o) { }
    
    void method(String s) { }
    
    method("hello");          // calls method(String)
    method((Object) "hello"); // calls method(Object)
    
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