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Asked: May 11, 20262026-05-11T04:07:12+00:00 2026-05-11T04:07:12+00:00

Consider following class class test { public: test(int x){ cout<< test \n; } };

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Consider following class

class test { public: test(int x){ cout<< 'test \n'; }  }; 

Now I want to create array of 50 objects of class test . I cannot change class test.

Objects can be created on heap or stack.

Creating objs on stack is not possible in this case since we dont have default constructor in class

test objs(1)[50]; /// Error... 

Now we may think of creating objs on heap like this..

test ** objs = NULL; objs = (test **) malloc( 50 * sizeof (test *)); for (int i =0; i<50 ; ++ i) {    objs[i] = new test(1); } 

I dont want to use malloc .Is there any other way??

If you guys can think of some more solutions , please post them…

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  1. 2026-05-11T04:07:12+00:00Added an answer on May 11, 2026 at 4:07 am

    You cannot create an array of objects, as in Foo foo [N], without a default constructor. It’s part of the language spec.

    Either do:

    test * objs [50]; for() objs[i] = new test(1). 

    You don’t need malloc(). You can just declare an array of pointers.

    c++decl> explain int * objs [50] declare objs as array 50 of pointer to int 

    But you probably ought to have some sort of automatic RAII-type destruction attached.


    OR subclass test publicly:

    class TempTest : public test { public:   TempTest() : test(1) {}   TempTest(int x) : test(x) {}   TempTest(const     test & theTest ) : test(theTest) {}   TempTest(const TempTest & theTest ) : test(theTest) {}   test & operator=( const     test & theTest ) { return test::operator=(theTest); }   test & operator=( const TempTest & theTest ) { return test::operator=(theTest); }   virtual ~TempTest() {} }; 

    and then:

    TempTest  array[50]; 

    You can treat every TempTest object as a test object.

    Note: operator=() & copy constructor are not inherited, so respecify as necessary.

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