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Home/ Questions/Q 3935002
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T23:46:49+00:00 2026-05-19T23:46:49+00:00

Consider following code: mynamespace.myclass = function() { this.myfunction = function() { alert("Original"); } }

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Consider following code:

mynamespace.myclass = function() {
    this.myfunction = function() { alert("Original"); }
}

What I’m trying to do is to overwrite myfunction from outside of mynamespace.myclass declaration.

While adding new functions through prototype seems to work ok, if I define a function with the same name the original function doesn’t get overwritten:

mynamespace.myclass.prototype.myfunction = function() { 
   alert("Overwritten");
}

Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-19T23:46:50+00:00Added an answer on May 19, 2026 at 11:46 pm

    That’s because myfunction is being added in the constructor, which happens after the prototype properties are added (so that the “Original” is in fact overwriting the “Overwritten”).

    You’ll have to mimic this behaviour, by overwriting mynamespace.myclass itself:

    var oldClass = mynamespace.myclass; // Copy original before overwriting
    mynamespace.myclass = function () {
        // Apply the original constructor on this object
        oldClass.apply(this, arguments);
    
        // Now overwrite the target function after construction
        this.myfunction = function () { alert("Overwritten"); };
    };
    mynamespace.prototype = oldClass.prototype; // Same prototype
    
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