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Home/ Questions/Q 684159
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T01:47:09+00:00 2026-05-14T01:47:09+00:00

Consider something like: struct Parameter { int a; Parameter(){a = 0;} void setA(int newA){a

  • 0

Consider something like:

struct Parameter
{
    int a;
    Parameter(){a = 0;}
    void setA(int newA){a = newA;}
};
struct MyClass
{
    void changeParameter(Parameter &p){ p.setA(-1);}
};

Well, let’s fast forward, and imagine I already wrapped those classes, exposing everything to python, and imagine also I instantiate an object of Parameter in the C++ code, which I pass to the python script, and that python script uses a MyClass object to modify the instance of Parameter I created at the beginning in the C++ code.

After that code executes, in C++ Parameter instance is unchanged!!! This means it was passed by value (or something alike :S), not by reference. But I thought I declared it to be passed by reference…

I can’t seem to find Boost::Python documentation about passing by reference (although there seems to be enough doc about returning by reference…). Can anyone give some hint or pointer please?

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  1. Editorial Team
    Editorial Team
    2026-05-14T01:47:10+00:00Added an answer on May 14, 2026 at 1:47 am

    Python doesn’t have references, so when you pass reference to python boost::python calls copy-ctor of your object.

    In this case you have two choices: Replace references with pointers (or smart-pointers) or pass into python your own ‘smart-reference’ object/wrapper.

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