Question

Consider the below example

int nCount[2] = {5,10};
int* ptrInt;
ptrInt = nCount;
cout<<ptrInt<<Endl;//this will print the address of arrar nCount

now consider this

char *str = "Idle mind is a devil's workshop";
int nLen = strlen(str);

char* ptr;
ptr = new char[nLen+1];

strcpy(ptr,str);

cout<<ptr<<endl;//this wil print the string 

but shouldnt this be printing the address of str. I am not quite getting the difference.

Answer 1

Since char*s are frequently used for storing strings, the ostream operator<< is overloaded for char* to print out the pointed-to string instead of the pointer.

If you want to output the pointer, you can cast the pointer to void* and then output that.