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Home/ Questions/Q 3332808
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T23:43:38+00:00 2026-05-17T23:43:38+00:00

Consider the class foo with two constructors defined like this: class foo { public:

  • 0

Consider the class foo with two constructors defined like this:

class foo
{
public:
    foo(const std::string& filename) {std::cout << "ctor 1" << std::endl;}
    foo(const bool some_flag = false) {std::cout << "ctor 2" << std::endl;}
};

Instantiate the class with a string literal, and guess which constructor is called?

foo a ("/path/to/file");

Output:

ctor 2

I don’t know about you, but I don’t find that the most intuitive behavior in programming history. I bet there is some clever reason for it, though, and I’d like to know what that might be?

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  1. Editorial Team
    Editorial Team
    2026-05-17T23:43:39+00:00Added an answer on May 17, 2026 at 11:43 pm

    It’s very common in C to write this

    void f(T* ptr) {
        if (ptr) {
            // ptr is not NULL
        }
    }
    

    You should make a const char* constructor.

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