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Home/ Questions/Q 8444573
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T09:25:37+00:00 2026-06-10T09:25:37+00:00

Consider the code given at the end, which makes use of jQuery Mobile to

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Consider the code given at the end, which makes use of jQuery Mobile to enhance buttons.

The first button (original button) appears when page loads:
enter image description here

The second button (inserted button) is inserted by clicking the yellow box:
enter image description here

The problem here is, the inserted button cannot catch up the CSS styles. This scenario is very common (and not specific to jQuery Mobile) when we work with AJAX, but I have never able to find a solution or workaround for this problem.

What can I do to enhance the inserted button with CSS styles?

<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
    <head>
        <title>title</title>
        <link rel="stylesheet" href="http://code.jquery.com/mobile/1.1.1/jquery.mobile-1.1.1.min.css" />
        <script src="http://code.jquery.com/jquery-1.7.1.min.js"></script>
        <script src="http://code.jquery.com/mobile/1.1.1/jquery.mobile-1.1.1.min.js"></script>          

        <script type="text/javascript">
            function insert(){
                $("#result").html('<input type="button" value="Inserted button"/>');
            }
        </script>

    </head>
    <body>
        <form>

            <p class="ui-body-e ui-corner-all" style="padding:5px" onclick="insert()">Click here to insert the button</p>

            <input type="button" value="Original button" />

            <div id="result">
                Button not inserted yet  
            </div>

        </form>
    </body>
</html>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T09:25:39+00:00Added an answer on June 10, 2026 at 9:25 am

    After you insert the button’s html:

    $("#result").html('<input type="button" value="Inserted button"/>');
    

    You can call .trigger('create') on its container to invoke the jQuery-mobile renderer on its contents, so your line would look like this:

    $("#result").html('<input type="button" value="Inserted button"/>').trigger('create');
    
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