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Home/ Questions/Q 933295
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T20:48:40+00:00 2026-05-15T20:48:40+00:00

Consider the following birthdays (as dob ): 1-Jun-68 1-Jun-69 When parsed with Python’s datetime.strptime(dob,

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Consider the following birthdays (as dob):

  • 1-Jun-68
  • 1-Jun-69

When parsed with Python’s datetime.strptime(dob, '%d-%b-%y') will yield:

  • datetime.datetime(2068, 6, 1, 0, 0)
  • datetime.datetime(1969, 6, 1, 0, 0)

Well of course they’re supposed to be born in the same decade but now it’s not even in the same century!

According to the docs this is perfectly valid behaviour:

When 2-digit years are accepted, they are converted according to
the POSIX or X/Open standard: values 69-99 are mapped to 1969-1999,
and values 0–68 are mapped to 2000–2068.

I understand why the function is set up like this but is there a way to work around this? Perhaps with defining your own ranges for 2-digit years?

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  1. Editorial Team
    Editorial Team
    2026-05-15T20:48:41+00:00Added an answer on May 15, 2026 at 8:48 pm

    If you’re always using it for birthdays, just subtract 100 if the year is after now:

    if d > datetime.now():
        d = datetime(d.year - 100, d.month, d.day)
    
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