Question

Consider the following C function.
Does opening the braces to create a local scope make compilers create a record on the stack to mantain the variables declared in the scope ?

void function()  
{  
    int q,r;
    ...
    {  
        int i = 0;
        int j = 3;  
        q = j + 1;  
    }
    ... 
}

If so , do compilers act the same with while blocks?

example:

void function()  
{  
    int q,r;
    ...    
    while(conditions)  
    {  
        int i = 0;  
        int j = 3;    
        q = j + 1;    
    }
    ... 
}

Answer 1

The arrangement of the stack is not specified by the C standard.

Curly braces ({}) introduce a new scope, so in principle, yes, this could create a new frame on the stack. But the compiler may choose to optimise this overhead away.