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Home/ Questions/Q 495985
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:38:36+00:00 2026-05-13T05:38:36+00:00

Consider the following code: byte[] bytes = new byte[] { 1, 2, 5, 0,

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Consider the following code:

byte[] bytes = new byte[] { 1, 2, 5, 0, 6 };
byte[] another = new byte[] { 1, 2, 5, 0, 6 };

Hashtable ht = new Hashtable();
ht.Add(bytes, "hi");
Assert.IsTrue(ht.ContainsKey(another));

Why does this assertion fail? Being an array of a primitive type shouldn’t use using the object reference, should it? So why would it return false? Is there anything I can do to make this hashtable work?

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  1. Editorial Team
    Editorial Team
    2026-05-13T05:38:36+00:00Added an answer on May 13, 2026 at 5:38 am

    Here’s a sample implementation:

      class Program {
        static void Main(string[] args) {
          byte[] bytes = new byte[] { 1, 2, 5, 0, 6 };
          byte[] another = new byte[] { 1, 2, 5, 0, 6 };
    
          Hashtable ht = new Hashtable(new ByteArrayComparer());
          ht.Add(bytes, "hi");
          System.Diagnostics.Debug.Assert(ht.ContainsKey(another));
        }
    
        private class ByteArrayComparer : IEqualityComparer {
          public int GetHashCode(object obj) {
            byte[] arr = obj as byte[];
            int hash = 0;
            foreach (byte b in arr) hash ^= b;
            return hash;
          }
          public new bool Equals(object x, object y) {
            byte[] arr1 = x as byte[];
            byte[] arr2 = y as byte[];
            if (arr1.Length != arr2.Length) return false;
            for (int ix = 0; ix < arr1.Length; ++ix)
              if (arr1[ix] != arr2[ix]) return false;
            return true;
          }
        }
      }
    

    You should use a stronger hash if you put thousands of arrays in the hash table. Check this post for an example.

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