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Home/ Questions/Q 8947743
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T12:50:43+00:00 2026-06-15T12:50:43+00:00

Consider the following code Class.prototype.init = function() { var self = this; var onComplete

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Consider the following code

Class.prototype.init = function() {
    var self = this;
    var onComplete = function() {
        self.a.doSomethingElse(self._go);
    };

    console.log(this); //prints Object {...}
    this.a.doSomething(onComplete); //onComplete is called inside a
};

Controller.prototype._go = function(map) {
    console.log(this); //prints 'Window'
};

The question is why this is equal to window inside _go function?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T12:50:44+00:00Added an answer on June 15, 2026 at 12:50 pm

    The binding of the object by calling a property only applies when directly calling it. When just accessing the property and calling it later on (by e.g. passing it to a callback), the object binding is not kept.

    The behaviour comes down to the following:

    var a = {
      b: function() {
        console.log(this);
      }
    };
    
    a.b(); // logs a, because called directly
    
    var func = a.b;
    func(); // logs window, because not called directly
    

    In your case, you could just as well pass Controller.prototype._go since it refers to the very same function. The solution is to use self._go.bind(self) to keep the binding.

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