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Home/ Questions/Q 6212931
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T06:36:17+00:00 2026-05-24T06:36:17+00:00

Consider the following code: $(.lcontainer a).click(function () { var current = $(this); var name

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Consider the following code:

$(".lcontainer a").click(function () {
    var current = $(this);
    var name = current.attr('href');
    document.getElementsByName('source')[0].value = name;
    var fPicture = "css/imgs/Flash.png";
    //If image is wrapped in link unwrap it
    var newLink = $('<a/>').attr('href', name);
    newLink.find('#prev').unwrap();
    if (extension == "jpg" || extension == "png" || extension == "gif" || extension == "bmp") {
        $(".mainCategory").html("Picture");
        document.getElementById('prev').src = name;
    }
    else if (extension == "swf") {
        $(".mainCategory").html("Game");
        document.getElementById('prev').src = fPicture;
        previewImage.wrap(newLink);
    }
    return false;
});
});

The logic is simple: if we have swf file put flash symbol and wrap the symbol with link pointing to this file. The problem: click another link and the symbol is not unwrapped.

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  1. Editorial Team
    Editorial Team
    2026-05-24T06:36:18+00:00Added an answer on May 24, 2026 at 6:36 am

    You’re creating a new link element with:

    var newLink = $('<a/>').attr('href', name);
    

    …so this:

    newLink.find('#prev').unwrap();
    

    … won’t find anything because newLink doesn’t have anything inside it yet.

    Are you certain you didn’t want to do something like this?

    $('#prev').unwrap();
    var newLink = $('<a/>').attr('href', name);
    
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