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Home/ Questions/Q 8749751
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T12:44:50+00:00 2026-06-13T12:44:50+00:00

Consider the following code: template <typename T> class C2 { public: T method() {

  • 0

Consider the following code:

template <typename T>
class C2 {
     public: 
             T method() { }
             int method2() { }
};

Compiling it with g++ -Wall -c -pedantic gives me the following warning:

test.cpp: In member function ‘int C2<T>::method2()’:
test.cpp:4:29: warning: no return statement in function returning non-void [-Wreturn-type]

Which is expected. The strange thing is that method() isn’t returning anything either. Why doesn’t that generate a warning, since instantiating C2 with T = int makes calls to both methods equally dangerous?

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  1. Editorial Team
    Editorial Team
    2026-06-13T12:44:50+00:00Added an answer on June 13, 2026 at 12:44 pm

    If you say T = void, then no return statement is needed.

    Just because you can use your template in a way that’s broken doesn’t mean you have to, and the com­piler may be giving you the benefit of the doubt.

    Also remember that member functions of a class template are only instantiated if and when used. So the way to actually cause an error is to have C2<char> x; x.method();, and that does indeed produce a warning.

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