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Home/ Questions/Q 123631
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Asked: May 11, 20262026-05-11T04:19:02+00:00 2026-05-11T04:19:02+00:00

Consider the following code Timer1 .Enabled := False; Timer1.Interval : = 300; For I

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Consider the following code

Timer1 .Enabled := False; Timer1.Interval : = 300; For I := 1 to NumberOfTimesNeed do Begin     Timer1 .Enabled := False;    //      Timer1 .Enabled := True;     // reset the timer to 0.30 seconds     TakesToLong     := False;    DoSomethingThatTakesTime;    // Application.ProcessMessages is called in the procedure     If TakesToLong = True then        TakeAction; End;  procedure Timer1Timer(Sender: TObject); begin    TakesToLong:= True; end; 

Question :

When I disable and then enable the Timer1 with

Timer1.Enabled := False; Timer1.Enabled := True; 

Does this reset the timer ?

i.e. will it always wait 0.30 Seconds before timing out.

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  1. 2026-05-11T04:19:02+00:00Added an answer on May 11, 2026 at 4:19 am

    Yes, it will. Setting Enabled to False will call the Windows API function KillTimer() if the timer was enabled before. Setting Enabled to True will call the Windows API function SetTimer() if the timer was not enabled before.

    It’s a standard idiom, which has been working since the times of Delphi 1.

    I would however implement your code in a different way:

    Start := GetSystemTicks; DoSomethingThatTakesTime; Duration := GetSystemTicks - Start;  if Duration > 300 then   TakeAction; 

    which would work without a timer, and without the need to call ProcessMessages() in the long-taking method. GetSystemTicks() is a function I have in a library, which does call timeGetTime() in Windows, and which was implemented differently for Kylix (don’t remember how, I purged that code long ago).

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