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Home/ Questions/Q 5846087
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T12:31:38+00:00 2026-05-22T12:31:38+00:00

Consider the following code, which simply calls a method on each member of a

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Consider the following code, which simply calls a method on each member of a list:

class Demo:
    def make_change(self):
        pass

foo = [Demo(), Demo(), Demo()]
map(lambda x: x.make_change(), foo)

Is there a way to accomplish this without the long-winded lambda syntax? For example, in Scala, something similar to map(_.make_change(), foo) works. Does Python have an equivalent?

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  1. Editorial Team
    Editorial Team
    2026-05-22T12:31:39+00:00Added an answer on May 22, 2026 at 12:31 pm

    It’s not very pythonic to use map just for side-effects

    so why not

    for item in foo:
        item.make_change()
    

    This will run faster than using map

    you can put it on one line if you insist, but I wouldn’t

    for item in foo:item.make_change()
    
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