Question

Consider the following code:

x = 4
y = 5
z = (y + x)

puts z

As you’d expect, the output is 9. If you introduce a newline:

x = 4
y = 5
z = y
+ x

puts z

Then it outputs 5. This makes sense, because it’s interpreted as two separate statements (z = y and +x).

However, I don’t understand how it works when you have a newline within parentheses:

x = 4
y = 5
z = (y
+ x)

puts z

The output is 4. Why?

Answer 1

(Disclaimer: I’m not a Ruby programmer at all. This is just a wild guess.)

With parens, you get z being assigned the value of

y
+x

Which evaluates to the value of the last statement executed.