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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T19:41:19+00:00 2026-05-12T19:41:19+00:00

Consider the following extension method in c#, Traverse: IEnumerable<T> Traverse<T>( this IEnumerable<T> source, Func<T,

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Consider the following extension method in c#, Traverse:

IEnumerable<T> Traverse<T>( this IEnumerable<T> source, 
                              Func<T, IEnumerable<T>> fnRecurse );

This method allows one to recurse through a tree as defined by T and whatever function causes T to return its subnodes.

Now consider the following implementation of T:

class Node
{
  public string Name;
  public List<Node> Children;
}

My goal is to write the shortest function possible that will return an IEnumerable
containing the fully qualified paths for every node in this tree. Something like:

var node = GetParentNode();
return node.Traverse( node => node.Children )
           .Select( node => GetParentName(node) + ":" + node.Name );

Obviously, adding a Parent property to Node makes the problem trivial. Instead I’d like to build my parent strings inside a functor somehow. I don’t think this would be too hard in C++ but I don’t see how to do it in C#. Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-12T19:41:19+00:00Added an answer on May 12, 2026 at 7:41 pm

    I think the trick is to simply not pass down a Node type. Instead pass down the Node and it’s qualified path. For example

    var node = GetTheStartNode();
    var start = new { Path = node.Name; Node = node };
    var paths = 
       start
         .Traverse( x => x.Node.Children.Select(
            c => new { .Path = x.Path + ":" c.Name; .Node=c) )
         .Select(x => x.Path);
    
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