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Asked: May 11, 20262026-05-11T10:48:48+00:00 2026-05-11T10:48:48+00:00

Consider the following HTML. If I have a JSON reference to the <button> element,

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Consider the following HTML. If I have a JSON reference to the <button> element, how can I get a reference to the outer <tr> element in both cases

<table id='my-table'>     <tr>         <td>             <button>Foo</button>         </td>         <td>             <div>                 <button>Bar</button>             </div>         </td>     </tr> </table>  <script type='text/js'>     $('#table button').click(function(){         //$(this).parent().parent() will work for the first row         //$(this).parent().parent().parent() will work for the second row         //is there a selector or some magic json one liner that will climb         //the DOM tree until it hits a TR, or do I have to code this myself         //each time?                     //$(this).????     }); </script> 

I know I could special case each condition, but I’m more interested ‘however deep you happen to be, climb the tree until you find element X’ style solution. Something like this, but more jQuery like/less-verbose

var climb = function(node, str_rule){     if($(node).is(str_rule)){         return node;     }     else if($(node).is('body')){         return false;     }     else{         return climb(node.parentNode, str_rule);     } };   

I know about the parent(expr) method, but from what I’ve seen is allows you filter parents one level up and NOT climb the tree until you find expr (I’d love code example proving me wrong)

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  1. 2026-05-11T10:48:49+00:00Added an answer on May 11, 2026 at 10:48 am

    The parents function does what you want:

    $(this).parents('tr:first'); 
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