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Home/ Questions/Q 8523435
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T07:24:32+00:00 2026-06-11T07:24:32+00:00

Consider the following JSF 2.x markup: <h:form id=form1> <h:inputText id=input value=#{testBacking.input}/> </h:form> <h:form id=form2>

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Consider the following JSF 2.x markup:

<h:form id="form1">

    <h:inputText id="input" value="#{testBacking.input}"/> 

</h:form>


<h:form id="form2">

    <h:commandButton value="go" action="#{testBacking.go()}">
        <f:ajax execute="@all" render="output"/>
    </h:commandButton>               
    <h:outputText id="output" value="#{testBacking.input}"/>

</h:form>

The action method as follows:

public void go() {
        System.out.println("go() is called");
         System.out.println("input: "+ input);
    }

The input value does not submitted to the server upon clicking the button.

Are there any ways to submit the input value to the server (while keeping the input in a different form)?

If you can only submit fields from the same form, then what is the different between the following two?

<f:ajax execute="@all" render="output"/>
<f:ajax execute="@form" render="output"/>
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  1. Editorial Team
    Editorial Team
    2026-06-11T07:24:34+00:00Added an answer on June 11, 2026 at 7:24 am

    A quick search of jsf execute=@all vs execute=@form yields some results:

    • JSF: Execute values of multiple forms
    • What is <f:ajax execute="@all"> really supposed to do? It POSTs only the enclosing form

    In essence, the JSF processing works ok but HTML only sends the form that contains the ajax (I suspect HTML specifies a separate request for each form).

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