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Home/ Questions/Q 8126577
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T07:11:49+00:00 2026-06-06T07:11:49+00:00

Consider the following methods static ComponentType & getTypeFor(const type_info &t){ ComponentType * type =

  • 0

Consider the following methods

static ComponentType & getTypeFor(const type_info &t){
        ComponentType * type = componentTypes[t.hash_code()];

        if(type == NULL)
        {
            type = new ComponentType();
            componentTypes[t.hash_code()] = type;
        }
        return *type;
};

static bitset<BITSIZE> getBit(const type_info &t){
    ComponentType & type = getTypeFor(t);
    return type.getBit();
}

I would call this as follows

ComponentManagerType::getBit(typeid(MyComponentClass)); 
// Not an instance, passing class name

Now as the ComponentManagerType suggests; this is only meant for Components. The problem as of right now is that any type can be passed. It won’t do any harm but an id and bitset will be created for a non-component object.

Q:
How can I enforce this method to accept only objects of base type Component?

I know there is no direct way. But I’m pretty much scratching my head over this.

Edit:
Added my own solution. Not sure if it’s kosher.

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  1. Editorial Team
    Editorial Team
    2026-06-06T07:11:51+00:00Added an answer on June 6, 2026 at 7:11 am

    There is no direct way; type_info is by design a minimal interface.

    I’d suggest you rewrite getBit as a template function callable as getBit<MyComponentClass>(). You can then check base types in the template (e.g. using boost::is_base_of; you could even enforce the requirement in the template function declaration using std::enable_if) and perform the typeid operation knowing that the base class is correct.

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