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Home/ Questions/Q 8106931
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T00:36:47+00:00 2026-06-06T00:36:47+00:00

Consider the following piece of code – class MyThread extends Thread { private int

  • 0

Consider the following piece of code –

class MyThread extends Thread {
    private int x = 5;

    public void run() {
        synchronized (this) // <-- what does it mean?
        {
            for (int i = 0; i < x; i++) {
                System.out.println(i);
            }
            notify();
        }
    }
}

class Test {
    public static void main(String[] args) {
        MyThread m = new MyThread();
        m.start();

        synchronized (m) {
            try {
                m.wait();
            } catch (InterruptedException e) {

            }
        }
    }
}

In the above example, does Thread m acquire the lock on itself?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T00:36:50+00:00Added an answer on June 6, 2026 at 12:36 am

    The current thread acquires the lock on the associated instance of the MyThread class.

    The synchronized(this) is locking the same object as synchronized(m) in main().

    Finally,

    public void run() {
        synchronized (this) {
    

    is exactly equivalent to

    public synchronized void run() {
    
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